4(x-5)+3(2x+3)=2(3-3x)+5(4x+1)

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Solution for 4(x-5)+3(2x+3)=2(3-3x)+5(4x+1) equation: 



4(x-5)+3(2x+3)=2(3-3x)+5(4x+1)

We move all terms to the left:

4(x-5)+3(2x+3)-(2(3-3x)+5(4x+1))=0

We add all the numbers together, and all the variables

4(x-5)+3(2x+3)-(2(-3x+3)+5(4x+1))=0

We multiply parentheses

4x+6x-(2(-3x+3)+5(4x+1))-20+9=0



We calculate terms in parentheses: -(2(-3x+3)+5(4x+1)), so:

2(-3x+3)+5(4x+1)

We multiply parentheses

-6x+20x+6+5

We add all the numbers together, and all the variables

14x+11

Back to the equation:

-(14x+11)



We add all the numbers together, and all the variables

10x-(14x+11)-11=0

We get rid of parentheses

10x-14x-11-11=0

We add all the numbers together, and all the variables

-4x-22=0

We move all terms containing x to the left, all other terms to the right

-4x=22

x=22/-4

x=-5+1/2

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