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4(x-5)+2=9x-2(4+2x)
We move all terms to the left:
4(x-5)+2-(9x-2(4+2x))=0
We add all the numbers together, and all the variables
4(x-5)-(9x-2(2x+4))+2=0
We multiply parentheses
4x-(9x-2(2x+4))-20+2=0
We calculate terms in parentheses: -(9x-2(2x+4)), so:We add all the numbers together, and all the variables
9x-2(2x+4)
We multiply parentheses
9x-4x-8
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
4x-(5x-8)-18=0
We get rid of parentheses
4x-5x+8-18=0
We add all the numbers together, and all the variables
-1x-10=0
We move all terms containing x to the left, all other terms to the right
-x=10
x=10/-1
x=-10
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