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4(x-5)+2=2(3-x)
We move all terms to the left:
4(x-5)+2-(2(3-x))=0
We add all the numbers together, and all the variables
4(x-5)-(2(-1x+3))+2=0
We multiply parentheses
4x-(2(-1x+3))-20+2=0
We calculate terms in parentheses: -(2(-1x+3)), so:We add all the numbers together, and all the variables
2(-1x+3)
We multiply parentheses
-2x+6
Back to the equation:
-(-2x+6)
4x-(-2x+6)-18=0
We get rid of parentheses
4x+2x-6-18=0
We add all the numbers together, and all the variables
6x-24=0
We move all terms containing x to the left, all other terms to the right
6x=24
x=24/6
x=4
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