4(x-4)=2(8-x)+6x

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Solution for 4(x-4)=2(8-x)+6x equation:



4(x-4)=2(8-x)+6x
We move all terms to the left:
4(x-4)-(2(8-x)+6x)=0
We add all the numbers together, and all the variables
4(x-4)-(2(-1x+8)+6x)=0
We multiply parentheses
4x-(2(-1x+8)+6x)-16=0
We calculate terms in parentheses: -(2(-1x+8)+6x), so:
2(-1x+8)+6x
We add all the numbers together, and all the variables
6x+2(-1x+8)
We multiply parentheses
6x-2x+16
We add all the numbers together, and all the variables
4x+16
Back to the equation:
-(4x+16)
We get rid of parentheses
4x-4x-16-16=0
We add all the numbers together, and all the variables
-32!=0
There is no solution for this equation

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