4(x-4)=10+5x+5+6-5x+11

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Solution for 4(x-4)=10+5x+5+6-5x+11 equation: 



4(x-4)=10+5x+5+6-5x+11

We move all terms to the left:

4(x-4)-(10+5x+5+6-5x+11)=0

We add all the numbers together, and all the variables

4(x-4)-32=0

We multiply parentheses

4x-16-32=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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