4(x-3/1)+5/2(x+2)=5/1(x+2)

Solution for 4(x-3/1)+5/2(x+2)=5/1(x+2) equation:

4(x-3/1)+5/2(x+2)=5/1(x+2)

We move all terms to the left:

4(x-3/1)+5/2(x+2)-(5/1(x+2))=0


Domain of the equation: 2(x+2)!=0

x∈R



Domain of the equation: 1(x+2))!=0

x∈R


We add all the numbers together, and all the variables

4(x-3)+5/2(x+2)-(5/1(x+2))=0

We multiply parentheses

4x+5/2(x+2)-(5/1(x+2))-12=0

We calculate fractions


4x+(5xx/(2(x+2)*1(x+2)))+(-10xx/(2(x+2)*1(x+2)))-12=0


We calculate terms in parentheses: +(5xx/(2(x+2)*1(x+2))), so:

5xx/(2(x+2)*1(x+2))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)



We calculate terms in parentheses: +(-10xx/(2(x+2)*1(x+2))), so:

-10xx/(2(x+2)*1(x+2))

We multiply all the terms by the denominator


-10xx

Back to the equation:

+(-10xx)


We get rid of parentheses

4x+5xx-10xx-12=0

We move all terms containing x to the left, all other terms to the right

4x+5xx-10xx=12