4(x-3)=x+x+4

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Solution for 4(x-3)=x+x+4 equation: 



4(x-3)=x+x+4

We move all terms to the left:

4(x-3)-(x+x+4)=0

We add all the numbers together, and all the variables

4(x-3)-(2x+4)=0

We multiply parentheses

4x-(2x+4)-12=0

We get rid of parentheses

4x-2x-4-12=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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