4(x-3)=8(2x-2)+4

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Solution for 4(x-3)=8(2x-2)+4 equation: 



4(x-3)=8(2x-2)+4

We move all terms to the left:

4(x-3)-(8(2x-2)+4)=0

We multiply parentheses

4x-(8(2x-2)+4)-12=0



We calculate terms in parentheses: -(8(2x-2)+4), so:

8(2x-2)+4

We multiply parentheses

16x-16+4

We add all the numbers together, and all the variables

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

4x-16x+12-12=0

We add all the numbers together, and all the variables

-12x=0

x=0/-12

x=0

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