4(x-3)=6(3+x)

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Solution for 4(x-3)=6(3+x) equation: 



4(x-3)=6(3+x)

We move all terms to the left:

4(x-3)-(6(3+x))=0

We add all the numbers together, and all the variables

4(x-3)-(6(x+3))=0

We multiply parentheses

4x-(6(x+3))-12=0



We calculate terms in parentheses: -(6(x+3)), so:

6(x+3)

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

4x-6x-18-12=0

We add all the numbers together, and all the variables

-2x-30=0

We move all terms containing x to the left, all other terms to the right

-2x=30

x=30/-2

x=-15

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