4(x-3)=5(x-3)-4

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Solution for 4(x-3)=5(x-3)-4 equation: 



4(x-3)=5(x-3)-4

We move all terms to the left:

4(x-3)-(5(x-3)-4)=0

We multiply parentheses

4x-(5(x-3)-4)-12=0



We calculate terms in parentheses: -(5(x-3)-4), so:

5(x-3)-4

We multiply parentheses

5x-15-4

We add all the numbers together, and all the variables

5x-19

Back to the equation:

-(5x-19)



We get rid of parentheses

4x-5x+19-12=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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