4(x-3)=5(x-2)

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Solution for 4(x-3)=5(x-2) equation: 



4(x-3)=5(x-2)

We move all terms to the left:

4(x-3)-(5(x-2))=0

We multiply parentheses

4x-(5(x-2))-12=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We get rid of parentheses

4x-5x+10-12=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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