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4(x-3)=3(2x+1)
We move all terms to the left:
4(x-3)-(3(2x+1))=0
We multiply parentheses
4x-(3(2x+1))-12=0
We calculate terms in parentheses: -(3(2x+1)), so:We get rid of parentheses
3(2x+1)
We multiply parentheses
6x+3
Back to the equation:
-(6x+3)
4x-6x-3-12=0
We add all the numbers together, and all the variables
-2x-15=0
We move all terms containing x to the left, all other terms to the right
-2x=15
x=15/-2
x=-7+1/2
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