4(x-3)=3(2+2x)

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Solution for 4(x-3)=3(2+2x) equation: 



4(x-3)=3(2+2x)

We move all terms to the left:

4(x-3)-(3(2+2x))=0

We add all the numbers together, and all the variables

4(x-3)-(3(2x+2))=0

We multiply parentheses

4x-(3(2x+2))-12=0



We calculate terms in parentheses: -(3(2x+2)), so:

3(2x+2)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

4x-6x-6-12=0

We add all the numbers together, and all the variables

-2x-18=0

We move all terms containing x to the left, all other terms to the right

-2x=18

x=18/-2

x=-9

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