4(x-3)=2-(x+4)

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Solution for 4(x-3)=2-(x+4) equation: 



4(x-3)=2-(x+4)

We move all terms to the left:

4(x-3)-(2-(x+4))=0

We multiply parentheses

4x-(2-(x+4))-12=0



We calculate terms in parentheses: -(2-(x+4)), so:

2-(x+4)

determiningTheFunctionDomain
-(x+4)+2

We get rid of parentheses

-x-4+2

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

-(-1x-2)



We get rid of parentheses

4x+1x+2-12=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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