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4(x-3)=2(5x+15)
We move all terms to the left:
4(x-3)-(2(5x+15))=0
We multiply parentheses
4x-(2(5x+15))-12=0
We calculate terms in parentheses: -(2(5x+15)), so:We get rid of parentheses
2(5x+15)
We multiply parentheses
10x+30
Back to the equation:
-(10x+30)
4x-10x-30-12=0
We add all the numbers together, and all the variables
-6x-42=0
We move all terms containing x to the left, all other terms to the right
-6x=42
x=42/-6
x=-7
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