4(x-3)=10x-6(x+12)

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Solution for 4(x-3)=10x-6(x+12) equation: 



4(x-3)=10x-6(x+12)

We move all terms to the left:

4(x-3)-(10x-6(x+12))=0

We multiply parentheses

4x-(10x-6(x+12))-12=0



We calculate terms in parentheses: -(10x-6(x+12)), so:

10x-6(x+12)

We multiply parentheses

10x-6x-72

We add all the numbers together, and all the variables

4x-72

Back to the equation:

-(4x-72)



We get rid of parentheses

4x-4x+72-12=0

We add all the numbers together, and all the variables

60!=0

There is no solution for this equation

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