4(x-3)=1/2(x2+5)

Solution for 4(x-3)=1/2(x2+5) equation:

4(x-3)=1/2(x2+5)

We move all terms to the left:

4(x-3)-(1/2(x2+5))=0


Domain of the equation: 2(x2+5))!=0

x∈R


We add all the numbers together, and all the variables

-(1/2(+x^2+5))+4(x-3)=0

We multiply parentheses

-(1/2(+x^2+5))+4x-12=0

We multiply all the terms by the denominator


-(1+4x*2(+x^2+5))-12*2(+x^2+5))=0


We calculate terms in parentheses: -(1+4x*2(+x^2+5)), so:

1+4x*2(+x^2+5)

determiningTheFunctionDomain
4x*2(+x^2+5)+1

Wy multiply elements

8x^2(++1

We use the square of the difference formula

8x^2(+1

Back to the equation:

-(8x^2(+1)


We add all the numbers together, and all the variables

-(8x^21-12*2(+x^2+5))=0


We calculate terms in parentheses: -(8x^21-12*2(+x^2+5)), so:

8x^21-12*2(+x^2+5)

We do not support expression: x^21