4(x-3)/2=(2x+5)/9

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Solution for 4(x-3)/2=(2x+5)/9 equation: 



4(x-3)/2=(2x+5)/9

We move all terms to the left:

4(x-3)/2-((2x+5)/9)=0

We calculate fractions


4x/()+(-((2x+5)*2)/()=0



We calculate terms in parentheses: +(-((2x+5)*2)/(), so:

-((2x+5)*2)/(

We multiply all the terms by the denominator


-((2x+5)*2)



We calculate terms in parentheses: -((2x+5)*2), so:

(2x+5)*2

We multiply parentheses

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

-4x-10

Back to the equation:

+(-4x-10)



We get rid of parentheses

4x/()-4x-10=0

We multiply all the terms by the denominator


4x-4x*()-10*()=0

We add all the numbers together, and all the variables

4x-4x*()=0

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