4(x-3)-5(x+2)=7(3x-1)

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Solution for 4(x-3)-5(x+2)=7(3x-1) equation: 



4(x-3)-5(x+2)=7(3x-1)

We move all terms to the left:

4(x-3)-5(x+2)-(7(3x-1))=0

We multiply parentheses

4x-5x-(7(3x-1))-12-10=0



We calculate terms in parentheses: -(7(3x-1)), so:

7(3x-1)

We multiply parentheses

21x-7

Back to the equation:

-(21x-7)



We add all the numbers together, and all the variables

-1x-(21x-7)-22=0

We get rid of parentheses

-1x-21x+7-22=0

We add all the numbers together, and all the variables

-22x-15=0

We move all terms containing x to the left, all other terms to the right

-22x=15

x=15/-22

x=-15/22

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