4(x-3)-2x=6(x-5)+8

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Solution for 4(x-3)-2x=6(x-5)+8 equation: 



4(x-3)-2x=6(x-5)+8

We move all terms to the left:

4(x-3)-2x-(6(x-5)+8)=0

We add all the numbers together, and all the variables

-2x+4(x-3)-(6(x-5)+8)=0

We multiply parentheses

-2x+4x-(6(x-5)+8)-12=0



We calculate terms in parentheses: -(6(x-5)+8), so:

6(x-5)+8

We multiply parentheses

6x-30+8

We add all the numbers together, and all the variables

6x-22

Back to the equation:

-(6x-22)



We add all the numbers together, and all the variables

2x-(6x-22)-12=0

We get rid of parentheses

2x-6x+22-12=0

We add all the numbers together, and all the variables

-4x+10=0

We move all terms containing x to the left, all other terms to the right

-4x=-10

x=-10/-4

x=2+1/2

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