4(x-3)-16=2(x-2)x=

Solution for 4(x-3)-16=2(x-2)x= equation:

4(x-3)-16=2(x-2)x=

We move all terms to the left:

4(x-3)-16-(2(x-2)x)=0

We multiply parentheses

4x-(2(x-2)x)-12-16=0


We calculate terms in parentheses: -(2(x-2)x), so:

2(x-2)x

We multiply parentheses

2x^2-4x

Back to the equation:

-(2x^2-4x)


We add all the numbers together, and all the variables

4x-(2x^2-4x)-28=0

We get rid of parentheses

-2x^2+4x+4x-28=0

We add all the numbers together, and all the variables

-2x^2+8x-28=0

a = -2; b = 8; c = -28;
Δ = b2-4ac
Δ = 82-4·(-2)·(-28)
Δ = -160
Delta is less than zero, so there is no solution for the equation