4(x-3)+x=5(x-4)+8

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Solution for 4(x-3)+x=5(x-4)+8 equation:


Simplifying
4(x + -3) + x = 5(x + -4) + 8

Reorder the terms:
4(-3 + x) + x = 5(x + -4) + 8
(-3 * 4 + x * 4) + x = 5(x + -4) + 8
(-12 + 4x) + x = 5(x + -4) + 8

Combine like terms: 4x + x = 5x
-12 + 5x = 5(x + -4) + 8

Reorder the terms:
-12 + 5x = 5(-4 + x) + 8
-12 + 5x = (-4 * 5 + x * 5) + 8
-12 + 5x = (-20 + 5x) + 8

Reorder the terms:
-12 + 5x = -20 + 8 + 5x

Combine like terms: -20 + 8 = -12
-12 + 5x = -12 + 5x

Add '12' to each side of the equation.
-12 + 12 + 5x = -12 + 12 + 5x

Combine like terms: -12 + 12 = 0
0 + 5x = -12 + 12 + 5x
5x = -12 + 12 + 5x

Combine like terms: -12 + 12 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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