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4(x-3)+6(x+2)=30
We move all terms to the left:
4(x-3)+6(x+2)-(30)=0
We multiply parentheses
4x+6x-12+12-30=0
We add all the numbers together, and all the variables
10x-30=0
We move all terms containing x to the left, all other terms to the right
10x=30
x=30/10
x=3
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