4(x-3)+5=7(x-1)+4

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Solution for 4(x-3)+5=7(x-1)+4 equation: 



4(x-3)+5=7(x-1)+4

We move all terms to the left:

4(x-3)+5-(7(x-1)+4)=0

We multiply parentheses

4x-(7(x-1)+4)-12+5=0



We calculate terms in parentheses: -(7(x-1)+4), so:

7(x-1)+4

We multiply parentheses

7x-7+4

We add all the numbers together, and all the variables

7x-3

Back to the equation:

-(7x-3)



We add all the numbers together, and all the variables

4x-(7x-3)-7=0

We get rid of parentheses

4x-7x+3-7=0

We add all the numbers together, and all the variables

-3x-4=0

We move all terms containing x to the left, all other terms to the right

-3x=4

x=4/-3

x=-1+1/3

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