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4(x-3)+5=6x-2(3+x)
We move all terms to the left:
4(x-3)+5-(6x-2(3+x))=0
We add all the numbers together, and all the variables
4(x-3)-(6x-2(x+3))+5=0
We multiply parentheses
4x-(6x-2(x+3))-12+5=0
We calculate terms in parentheses: -(6x-2(x+3)), so:We add all the numbers together, and all the variables
6x-2(x+3)
We multiply parentheses
6x-2x-6
We add all the numbers together, and all the variables
4x-6
Back to the equation:
-(4x-6)
4x-(4x-6)-7=0
We get rid of parentheses
4x-4x+6-7=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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