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4(x-3)+2x=3(x+5)
We move all terms to the left:
4(x-3)+2x-(3(x+5))=0
We add all the numbers together, and all the variables
2x+4(x-3)-(3(x+5))=0
We multiply parentheses
2x+4x-(3(x+5))-12=0
We calculate terms in parentheses: -(3(x+5)), so:We add all the numbers together, and all the variables
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
6x-(3x+15)-12=0
We get rid of parentheses
6x-3x-15-12=0
We add all the numbers together, and all the variables
3x-27=0
We move all terms containing x to the left, all other terms to the right
3x=27
x=27/3
x=9
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