4(x-3)+2x=3(2x-4)

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Solution for 4(x-3)+2x=3(2x-4) equation: 



4(x-3)+2x=3(2x-4)

We move all terms to the left:

4(x-3)+2x-(3(2x-4))=0

We add all the numbers together, and all the variables

2x+4(x-3)-(3(2x-4))=0

We multiply parentheses

2x+4x-(3(2x-4))-12=0



We calculate terms in parentheses: -(3(2x-4)), so:

3(2x-4)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

6x-(6x-12)-12=0

We get rid of parentheses

6x-6x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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