4(x-3)+12=15-5(+6)

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Solution for 4(x-3)+12=15-5(+6) equation: 



4(x-3)+12=15-5(+6)

We move all terms to the left:

4(x-3)+12-(15-5(+6))=0

We add all the numbers together, and all the variables

4(x-3)+12-(15-56)=0

We add all the numbers together, and all the variables

4(x-3)+53=0

We multiply parentheses

4x-12+53=0

We add all the numbers together, and all the variables

4x+41=0

We move all terms containing x to the left, all other terms to the right

4x=-41

x=-41/4

x=-10+1/4

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