4(x-2)=7-(5x+15+3(x-4))

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Solution for 4(x-2)=7-(5x+15+3(x-4)) equation: 



4(x-2)=7-(5x+15+3(x-4))

We move all terms to the left:

4(x-2)-(7-(5x+15+3(x-4)))=0

We multiply parentheses

4x-(7-(5x+15+3(x-4)))-8=0



We calculate terms in parentheses: -(7-(5x+15+3(x-4))), so:

7-(5x+15+3(x-4))

determiningTheFunctionDomain
-(5x+15+3(x-4))+7



We calculate terms in parentheses: -(5x+15+3(x-4)), so:

5x+15+3(x-4)

determiningTheFunctionDomain
5x+3(x-4)+15

We multiply parentheses

5x+3x-12+15

We add all the numbers together, and all the variables

8x+3

Back to the equation:

-(8x+3)



We get rid of parentheses

-8x-3+7

We add all the numbers together, and all the variables

-8x+4

Back to the equation:

-(-8x+4)



We get rid of parentheses

4x+8x-4-8=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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