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4(x-2)=2(x-2)+2x
We move all terms to the left:
4(x-2)-(2(x-2)+2x)=0
We multiply parentheses
4x-(2(x-2)+2x)-8=0
We calculate terms in parentheses: -(2(x-2)+2x), so:We get rid of parentheses
2(x-2)+2x
We add all the numbers together, and all the variables
2x+2(x-2)
We multiply parentheses
2x+2x-4
We add all the numbers together, and all the variables
4x-4
Back to the equation:
-(4x-4)
4x-4x+4-8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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