4(x-2)=2(x+3)-40

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Solution for 4(x-2)=2(x+3)-40 equation: 



4(x-2)=2(x+3)-40

We move all terms to the left:

4(x-2)-(2(x+3)-40)=0

We multiply parentheses

4x-(2(x+3)-40)-8=0



We calculate terms in parentheses: -(2(x+3)-40), so:

2(x+3)-40

We multiply parentheses

2x+6-40

We add all the numbers together, and all the variables

2x-34

Back to the equation:

-(2x-34)



We get rid of parentheses

4x-2x+34-8=0

We add all the numbers together, and all the variables

2x+26=0

We move all terms containing x to the left, all other terms to the right

2x=-26

x=-26/2

x=-13

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