4(x-2)-2=(x-4)+2x

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Solution for 4(x-2)-2=(x-4)+2x equation: 



4(x-2)-2=(x-4)+2x

We move all terms to the left:

4(x-2)-2-((x-4)+2x)=0

We multiply parentheses

4x-((x-4)+2x)-8-2=0



We calculate terms in parentheses: -((x-4)+2x), so:

(x-4)+2x

We add all the numbers together, and all the variables

2x+(x-4)

We get rid of parentheses

2x+x-4

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

4x-(3x-4)-10=0

We get rid of parentheses

4x-3x+4-10=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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