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4(x-2)-12(4)=12(x-3/4)
We move all terms to the left:
4(x-2)-12(4)-(12(x-3/4))=0
We add all the numbers together, and all the variables
4(x-2)-(12(+x-3/4))-124=0
We multiply parentheses
4x-(12(+x-3/4))-8-124=0
We multiply all the terms by the denominator
4x*4))-(12(+x-3-8*4))-124*4))=0
We add all the numbers together, and all the variables
4x*4))-(12(x-35))-124*4))=0
We add all the numbers together, and all the variables
4x*4))-(12(x=0
Wy multiply elements
16x^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{32}=0$
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