4(x-2)+3(2x+6)=60+5(x-2)

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Solution for 4(x-2)+3(2x+6)=60+5(x-2) equation: 



4(x-2)+3(2x+6)=60+5(x-2)

We move all terms to the left:

4(x-2)+3(2x+6)-(60+5(x-2))=0

We multiply parentheses

4x+6x-(60+5(x-2))-8+18=0



We calculate terms in parentheses: -(60+5(x-2)), so:

60+5(x-2)

determiningTheFunctionDomain
5(x-2)+60

We multiply parentheses

5x-10+60

We add all the numbers together, and all the variables

5x+50

Back to the equation:

-(5x+50)



We add all the numbers together, and all the variables

10x-(5x+50)+10=0

We get rid of parentheses

10x-5x-50+10=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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