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4(x-2)+2x-3=6(x-1)-10
We move all terms to the left:
4(x-2)+2x-3-(6(x-1)-10)=0
We add all the numbers together, and all the variables
2x+4(x-2)-(6(x-1)-10)-3=0
We multiply parentheses
2x+4x-(6(x-1)-10)-8-3=0
We calculate terms in parentheses: -(6(x-1)-10), so:We add all the numbers together, and all the variables
6(x-1)-10
We multiply parentheses
6x-6-10
We add all the numbers together, and all the variables
6x-16
Back to the equation:
-(6x-16)
6x-(6x-16)-11=0
We get rid of parentheses
6x-6x+16-11=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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