4(x-2)+(3x+5)=28

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Solution for 4(x-2)+(3x+5)=28 equation: 



4(x-2)+(3x+5)=28

We move all terms to the left:

4(x-2)+(3x+5)-(28)=0

We multiply parentheses

4x+(3x+5)-8-28=0

We get rid of parentheses

4x+3x+5-8-28=0

We add all the numbers together, and all the variables

7x-31=0

We move all terms containing x to the left, all other terms to the right

7x=31

x=31/7

x=4+3/7

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