4(x-12)=2(x+10)

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Solution for 4(x-12)=2(x+10) equation: 



4(x-12)=2(x+10)

We move all terms to the left:

4(x-12)-(2(x+10))=0

We multiply parentheses

4x-(2(x+10))-48=0



We calculate terms in parentheses: -(2(x+10)), so:

2(x+10)

We multiply parentheses

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

4x-2x-20-48=0

We add all the numbers together, and all the variables

2x-68=0

We move all terms containing x to the left, all other terms to the right

2x=68

x=68/2

x=34

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