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4(x-1)-5=3(x+2)
We move all terms to the left:
4(x-1)-5-(3(x+2))=0
We multiply parentheses
4x-(3(x+2))-4-5=0
We calculate terms in parentheses: -(3(x+2)), so:We add all the numbers together, and all the variables
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
4x-(3x+6)-9=0
We get rid of parentheses
4x-3x-6-9=0
We add all the numbers together, and all the variables
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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