4(x-1)+x-3=-2(x+4)+(x-1)

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Solution for 4(x-1)+x-3=-2(x+4)+(x-1) equation: 



4(x-1)+x-3=-2(x+4)+(x-1)

We move all terms to the left:

4(x-1)+x-3-(-2(x+4)+(x-1))=0

We add all the numbers together, and all the variables

x+4(x-1)-(-2(x+4)+(x-1))-3=0

We multiply parentheses

x+4x-(-2(x+4)+(x-1))-4-3=0



We calculate terms in parentheses: -(-2(x+4)+(x-1)), so:

-2(x+4)+(x-1)

We multiply parentheses

-2x+(x-1)-8

We get rid of parentheses

-2x+x-1-8

We add all the numbers together, and all the variables

-1x-9

Back to the equation:

-(-1x-9)



We add all the numbers together, and all the variables

5x-(-1x-9)-7=0

We get rid of parentheses

5x+1x+9-7=0

We add all the numbers together, and all the variables

6x+2=0

We move all terms containing x to the left, all other terms to the right

6x=-2

x=-2/6

x=-1/3

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