4(x-1)+5=2(x+3)+1

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Solution for 4(x-1)+5=2(x+3)+1 equation: 



4(x-1)+5=2(x+3)+1

We move all terms to the left:

4(x-1)+5-(2(x+3)+1)=0

We multiply parentheses

4x-(2(x+3)+1)-4+5=0



We calculate terms in parentheses: -(2(x+3)+1), so:

2(x+3)+1

We multiply parentheses

2x+6+1

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We add all the numbers together, and all the variables

4x-(2x+7)+1=0

We get rid of parentheses

4x-2x-7+1=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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