4(x+6)+x-3=41+10(2x+1)

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Solution for 4(x+6)+x-3=41+10(2x+1) equation: 



4(x+6)+x-3=41+10(2x+1)

We move all terms to the left:

4(x+6)+x-3-(41+10(2x+1))=0

We add all the numbers together, and all the variables

x+4(x+6)-(41+10(2x+1))-3=0

We multiply parentheses

x+4x-(41+10(2x+1))+24-3=0



We calculate terms in parentheses: -(41+10(2x+1)), so:

41+10(2x+1)

determiningTheFunctionDomain
10(2x+1)+41

We multiply parentheses

20x+10+41

We add all the numbers together, and all the variables

20x+51

Back to the equation:

-(20x+51)



We add all the numbers together, and all the variables

5x-(20x+51)+21=0

We get rid of parentheses

5x-20x-51+21=0

We add all the numbers together, and all the variables

-15x-30=0

We move all terms containing x to the left, all other terms to the right

-15x=30

x=30/-15

x=-2

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