4(x+5)=3(x-2)-2(x-2)

Solution for 4(x+5)=3(x-2)-2(x-2) equation:

4(x+5)=3(x-2)-2(x-2)

We move all terms to the left:

4(x+5)-(3(x-2)-2(x-2))=0

We multiply parentheses

4x-(3(x-2)-2(x-2))+20=0


We calculate terms in parentheses: -(3(x-2)-2(x-2)), so:

3(x-2)-2(x-2)

We multiply parentheses

3x-2x-6+4

We add all the numbers together, and all the variables

x-2

Back to the equation:

-(x-2)


We get rid of parentheses

4x-x+2+20=0

We add all the numbers together, and all the variables

3x+22=0

We move all terms containing x to the left, all other terms to the right

3x=-22

x=-22/3

x=-7+1/3