4(x+5)=27+5x

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Solution for 4(x+5)=27+5x equation: 



4(x+5)=27+5x

We move all terms to the left:

4(x+5)-(27+5x)=0

We add all the numbers together, and all the variables

4(x+5)-(5x+27)=0

We multiply parentheses

4x-(5x+27)+20=0

We get rid of parentheses

4x-5x-27+20=0

We add all the numbers together, and all the variables

-1x-7=0

We move all terms containing x to the left, all other terms to the right

-x=7

x=7/-1

x=-7

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