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4(x+5)-8=2x+2(4+x)
We move all terms to the left:
4(x+5)-8-(2x+2(4+x))=0
We add all the numbers together, and all the variables
4(x+5)-(2x+2(x+4))-8=0
We multiply parentheses
4x-(2x+2(x+4))+20-8=0
We calculate terms in parentheses: -(2x+2(x+4)), so:We add all the numbers together, and all the variables
2x+2(x+4)
We multiply parentheses
2x+2x+8
We add all the numbers together, and all the variables
4x+8
Back to the equation:
-(4x+8)
4x-(4x+8)+12=0
We get rid of parentheses
4x-4x-8+12=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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