4(x+5)-3=6(x-2)-1

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Solution for 4(x+5)-3=6(x-2)-1 equation: 



4(x+5)-3=6(x-2)-1

We move all terms to the left:

4(x+5)-3-(6(x-2)-1)=0

We multiply parentheses

4x-(6(x-2)-1)+20-3=0



We calculate terms in parentheses: -(6(x-2)-1), so:

6(x-2)-1

We multiply parentheses

6x-12-1

We add all the numbers together, and all the variables

6x-13

Back to the equation:

-(6x-13)



We add all the numbers together, and all the variables

4x-(6x-13)+17=0

We get rid of parentheses

4x-6x+13+17=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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