4(x+5)-2(x-8)=5(x-3)+20

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Solution for 4(x+5)-2(x-8)=5(x-3)+20 equation: 



4(x+5)-2(x-8)=5(x-3)+20

We move all terms to the left:

4(x+5)-2(x-8)-(5(x-3)+20)=0

We multiply parentheses

4x-2x-(5(x-3)+20)+20+16=0



We calculate terms in parentheses: -(5(x-3)+20), so:

5(x-3)+20

We multiply parentheses

5x-15+20

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

2x-(5x+5)+36=0

We get rid of parentheses

2x-5x-5+36=0

We add all the numbers together, and all the variables

-3x+31=0

We move all terms containing x to the left, all other terms to the right

-3x=-31

x=-31/-3

x=10+1/3

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