4(x+5)+x=8(x+2)+1

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Solution for 4(x+5)+x=8(x+2)+1 equation: 



4(x+5)+x=8(x+2)+1

We move all terms to the left:

4(x+5)+x-(8(x+2)+1)=0

We add all the numbers together, and all the variables

x+4(x+5)-(8(x+2)+1)=0

We multiply parentheses

x+4x-(8(x+2)+1)+20=0



We calculate terms in parentheses: -(8(x+2)+1), so:

8(x+2)+1

We multiply parentheses

8x+16+1

We add all the numbers together, and all the variables

8x+17

Back to the equation:

-(8x+17)



We add all the numbers together, and all the variables

5x-(8x+17)+20=0

We get rid of parentheses

5x-8x-17+20=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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