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4(x+5)+3(x-2)=x-4
We move all terms to the left:
4(x+5)+3(x-2)-(x-4)=0
We multiply parentheses
4x+3x-(x-4)+20-6=0
We get rid of parentheses
4x+3x-x+4+20-6=0
We add all the numbers together, and all the variables
6x+18=0
We move all terms containing x to the left, all other terms to the right
6x=-18
x=-18/6
x=-3
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