4(x+4)=3(x-4)+x

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Solution for 4(x+4)=3(x-4)+x equation: 


Simplifying
4(x + 4) = 3(x + -4) + x

Reorder the terms:
4(4 + x) = 3(x + -4) + x
(4 * 4 + x * 4) = 3(x + -4) + x
(16 + 4x) = 3(x + -4) + x

Reorder the terms:
16 + 4x = 3(-4 + x) + x
16 + 4x = (-4 * 3 + x * 3) + x
16 + 4x = (-12 + 3x) + x

Combine like terms: 3x + x = 4x
16 + 4x = -12 + 4x

Add '-4x' to each side of the equation.
16 + 4x + -4x = -12 + 4x + -4x

Combine like terms: 4x + -4x = 0
16 + 0 = -12 + 4x + -4x
16 = -12 + 4x + -4x

Combine like terms: 4x + -4x = 0
16 = -12 + 0
16 = -12

Solving
16 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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