4(x+4)=3(x+1)+8

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Solution for 4(x+4)=3(x+1)+8 equation: 



4(x+4)=3(x+1)+8

We move all terms to the left:

4(x+4)-(3(x+1)+8)=0

We multiply parentheses

4x-(3(x+1)+8)+16=0



We calculate terms in parentheses: -(3(x+1)+8), so:

3(x+1)+8

We multiply parentheses

3x+3+8

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

4x-3x-11+16=0

We add all the numbers together, and all the variables

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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